Charge of Radon Nucleus: 86 Protons -1.6x10^-19 C

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The total charge of a radon nucleus, which contains 86 protons, is calculated by multiplying the number of protons by the charge of a proton, approximately +1.6x10^-19 C. Since the nucleus is positively charged, the correct calculation is 86 protons times +1.6x10^-19 C, resulting in a total charge of +1.376x10^-17 C. The confusion arose from mistakenly using the charge of an electron instead of a proton. It's essential to remember that protons carry a positive charge. Understanding the distinction between the charges of protons and electrons is crucial for solving this type of problem.
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Hi, this problem is killing me.

What is the total charge of the radon nucleus? (The neutral radon atom has 86 electrons.)

The units is in Coulombs so I figured since they were asking for the charge of just the nucleus then it would be 86 protons times -1.6x10^-19 C. But that didn't work, I've tried every answer I can think of but it isn't working. (its like an online homework thing...i have only a few tries left and i need this answer to continue the rest) Please please help! Thanks!
 
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oh my god, sorry i didn't see that sticky about hw. I'll post somewhere else...sorry!
 
-1.6x10^-19 C is the charge on an electron.

A proton is positively charged, and if there are 86 of them, then 86 * the charge of one proton is correct.

Be careful of + and -.
 

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