Charge of three small spheres when connected to a big one

In summary: You can see that the final charge on the small sphere is ## \frac{Q_1Q_2}{Q_1 + Q_2}##, the two charges divided by the sum of the two charges.In summary, we can use the equations V = kQ/r and the assumption that all sphere radii are small compared to the distances between them to derive an expression for the charge of the last small sphere in terms of the charges on the first two spheres. The final charge on the small sphere is ## \frac{Q_1Q_2}{Q_1 + Q_2}##, the two charges divided by the sum of the two charges.
  • #1
Rugile
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1

Homework Statement


Three small metal solid uncharged spheres are put on vertexes of an equilateral triangle. Then they all one by one are connected to a big conducting solid sphere, which is at the same distance from all the small ones, by a wire. Thus the first sphere is charged to q1 and the second one - to q2. Find the charge of the last small sphere if the potential of the big one does not change.


Homework Equations



[itex] V = kq/r [/itex]

The Attempt at a Solution



No idea how to do this one :( I was maybe thinking about the conservation of charge, but if the potential of the big sphere does not change, I'm not able to apply that conservation law. As I understand, all the small spheres are of the same potential when connected, but I'm not sure what to do with it. And does it matter whether the big sphere is at the same distance from the three small ones or not?

I'm completely lost. Any help appreciated!
 
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  • #2
It doesn't say, but I presume each connection is broken before the next one is made.
Let the potential of the large sphere be V. When a given small sphere is connected to it, what potential does it become? What are the contributors to the potential at that sphere?
 
  • #3
Well I guess then the small sphere it becomes potential V as well?
I do not understand the second question completely - but as I understand, you are asking what influences the potential of the second sphere? Is it charge?
 
  • #4
Rugile said:
Well I guess then the small sphere it becomes potential V as well?
I do not understand the second question completely - but as I understand, you are asking what influences the potential of the second sphere? Is it charge?

Let's back up for a moment and just consider two conducting spheres.
Let their centres be distance D apart, total charges Q1, Q2, and the radii R1, R2.
Where are the charges distributed on sphere 1?
What is the potential at the centre of sphere 1?

Edit: I'm not sure I can answer that last question myself... I might invite others into the thread.
 
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  • #5
Okay, so the charges on sphere 1 are distributed on the surface, I think?
And the potential must be [itex] V = \frac{kQ_1}{R_1} + \frac{kQ_2}{D} [/itex] ? Is that right?
But how does that help in the original problem? We don't know radii or distance..
 
  • #6
Rugile said:
Okay, so the charges on sphere 1 are distributed on the surface, I think?
And the potential must be [itex] V = \frac{kQ_1}{R_1} + \frac{kQ_2}{D} [/itex] ? Is that right?
But how does that help in the original problem? We don't know radii or distance..
Not knowing those distances shouldn't matter. The same distances will arise in equations for q1, q2 and q3, so we can eliminate them and arrive at an expression for q3 in terms of q1 and q2.
The problem, though, is that ## \frac{kQ_2}{D}## is wrong. The very presence of the three small spheres shifts the charge distribution on the large sphere and on each other. When charge flows from the large sphere to the first small sphere it all shifts again.
I've put a request for help on the homework helpers' page, but no nibbles yet.
 
  • #7
haruspex said:
Not knowing those distances shouldn't matter. The same distances will arise in equations for q1, q2 and q3, so we can eliminate them and arrive at an expression for q3 in terms of q1 and q2.
The problem, though, is that ## \frac{kQ_2}{D}## is wrong. The very presence of the three small spheres shifts the charge distribution on the large sphere and on each other. When charge flows from the large sphere to the first small sphere it all shifts again.
I've put a request for help on the homework helpers' page, but no nibbles yet.
Had a response from mfb, suggesting we assume all the sphere radii are small compared with the distances between the spheres. I don't like it since we were given no basis for assuming that applies to the large sphere, but it does yield an answer. It allows us to treat all surface charge distributions as uniform. I.e. you can use ## \frac{kQ_2}{D}##.
So apply that to the large sphere and the first small sphere. Then do the same equation for the second small sphere, but adding in the potential from the first small sphere.
 
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  • #8
So then let's say the charge of the big sphere is [itex] Q [/itex] and its potential is [itex]V[/itex]. Then when we connect the first small sphere its potential now is V as well, and the eq. [itex]V_1 = V = \frac{kQ}{D}+\frac{kQ_1}{r}[/itex]. And the second sphere's potential would be [itex]V_2 = V = \frac{kQ}{D} + \frac{kQ_1}{d} + {kQ_2}{r} [/itex]. From that we can derive [itex]V_1 = V_2 => \frac{kQ}{D}+\frac{kQ_1}{r} = \frac{kQ}{D} + \frac{kQ_1}{d} + \frac{kQ_2}{r} => r = \frac{(Q_1 - Q_2)d}{Q_1} [/itex]. Is that correct? Then the rest is totally clear :)

A huge thank to you!
 
  • #9
Rugile said:
So then let's say the charge of the big sphere is [itex] Q [/itex] and its potential is [itex]V[/itex]. Then when we connect the first small sphere its potential now is V as well, and the eq. [itex]V_1 = V = \frac{kQ}{D}+\frac{kQ_1}{r}[/itex]. And the second sphere's potential would be [itex]V_2 = V = \frac{kQ}{D} + \frac{kQ_1}{d} + {kQ_2}{r} [/itex]. From that we can derive [itex]V_1 = V_2 => \frac{kQ}{D}+\frac{kQ_1}{r} = \frac{kQ}{D} + \frac{kQ_1}{d} + \frac{kQ_2}{r} => r = \frac{(Q_1 - Q_2)d}{Q_1} [/itex]. Is that correct? Then the rest is totally clear :)

A huge thank to you!

That all looks right.
 

FAQ: Charge of three small spheres when connected to a big one

What is the charge of the three small spheres when connected to the big one?

The charge of the three small spheres will be evenly distributed among them and will depend on the charge of the big sphere. If the big sphere has a positive charge, the small spheres will also have a positive charge. If the big sphere has a negative charge, the small spheres will have a negative charge.

What happens to the charge of the big sphere when connected to the three small spheres?

The charge of the big sphere will remain the same. However, the total charge of the system will be divided among the four spheres, resulting in a decrease in the charge of the big sphere.

Can the charge of the small spheres be greater than the charge of the big sphere?

No, the charge of the small spheres can never be greater than the charge of the big sphere. The charge will always be evenly distributed among the spheres, with the big sphere having the largest share.

What happens to the charge of the small spheres when they are disconnected from the big one?

The charge of the small spheres will remain the same as it was when they were connected to the big sphere. The charge distribution among the small spheres will not change unless they come in contact with another charged object.

How does the distance between the spheres affect the charge distribution?

The distance between the spheres does not affect the charge distribution. As long as the spheres are connected, the charge will be evenly distributed among them regardless of the distance between them.

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