Charge on 7 mF Capacitor Connected to 1 V Battery

  • Thread starter Thread starter GravityGirl
  • Start date Start date
  • Tags Tags
    Capacitance
AI Thread Summary
When three capacitors of 5, 7, and 2 mF are connected in series to a 1 V battery, the charge on each capacitor is the same, but the voltage across each varies. The formula C=Q/V indicates that the charge (Q) can be calculated using the total capacitance in series. The total capacitance for capacitors in series is given by 1/C_total = 1/C1 + 1/C2 + 1/C3, leading to a different charge value than initially calculated. The correct approach reveals that the charge on the positive plate of the 7 mF capacitor is not simply 7x10^-6 C, as the voltage across it will differ from the total voltage. Understanding the series connection is crucial for accurate calculations.
GravityGirl
Messages
28
Reaction score
0
Three capacitors of capacitance 5, 7, and 2 mF respectively, are connected in series to a 1 V battery. What is the charge on the positive plate of the 7 mF capacitor?

so if the capacitors are all connected to the battery... than all of them have to have a electrial potential of 1 v

since C=Q/V, then CV=Q

and then i have (7 x10^-6 F)*1V=Q which is 7x10^-6 C

that is what i am getting, but it seems to be wrong. please help me out
 
Physics news on Phys.org
The capacitors are in series, so there is no requirement that they must have the same voltage across them.

- Warren
 
ok i got it.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

What will be the final voltage across the 2 micro-farad capacitor?
Replies
26
Views
2K
Comparing energy lost by the battery & energy gained by the capacitor.
Replies
5
Views
2K
Question about charged capacitors and inserting a dielectric into one
Replies
3
Views
1K
Charge on a grounded conducting sphere in a uniform electric field, after ungrounding and movement
Replies
1
Views
1K
Questions about a capacitor with 4 parallel plates
Replies
14
Views
1K
Capacitor Questions Charging and Discharging
Replies
4
Views
3K
Redistribution of Pre-Charged Capacitors
Replies
11
Views
3K
How to find the charge on each capacitor
Replies
3
Views
2K
Which quantities are not the same for this capacitor setup?
Replies
5
Views
2K
Ranking charge stored on three capacitors by a battery
Replies
6
Views
3K

Hot Threads

Recent Insights

Back
Top