Calculating Electric Field for Charged Ring on x,y Axes

[mickry]

Homework Statement

I have the field at the center of a charged ring on the x,y axes (top half has charge density of -lambda, bottom is +lambda lambda=la) to be
E=(lay^)/(2pi epsR) (eps=epsilon) i can't find the potential for this, R=radius,
Can anyone help?

Homework Equations

The Attempt at a Solution

 

[Saketh]

Normally, it's easier to find the potential first, as it is a scalar, and then take the partial derivative with respect to the distance variable to determine the E-Field.

In this case, your expression doesn't make sense.

<br /> E = \frac{\lambda y}{2 \pi \epsilon_0 R}<br />

Are you sure that's correct? Because that implies that as you get further away from the ring, the e-field increases, which doesn't make sense.