Checking the answer to complex number question

In summary, the equation connecting x and y for which (z-1)/(z+1) has an argument \alpha is given by x² + (y-a)² = b², where tan\alpha = \frac{2y}{x^2+y^2-1}.
  • #1
rock.freak667
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Homework Statement


Find an equation connecting x and y for which (z-1)/(z+1) has an argument [itex]\alpha[/itex]


Homework Equations


z=x+iy

arg(z)=tan-1(y/x)


The Attempt at a Solution



[tex]\frac{z-1}{z+1}[/tex]

Substituting z=x+iy

[tex]\Rightarrow \frac{z-1}{z+1}=\frac{(x-1)+iy}{(x+1)+iy}[/tex]

Realizing

[tex]\frac{(x+1)(x-1)+iy(x+1)-iy(x-1)-i^2y^2}{(x+1)^2+y^2}[/tex]

Re:i2=-1

[tex]= \frac{x^2+y^2-1}{(x+1)^2+y^2} +i \frac{2y}{(x+1)^2+y^2}[/tex]

Thus

[tex]tan\alpha = \frac{2y}{x^2+y^2-1}[/tex]

Is this correct? Or should I just put in the form of a circle?
 
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  • #2
rock.freak667 said:
Find an equation connecting x and y for which (z-1)/(z+1) has an argument [itex]\alpha[/itex]

Thus

[tex]tan\alpha = \frac{2y}{x^2+y^2-1}[/tex]

Is this correct? Or should I just put in the form of a circle

Hi rock.freak667! :smile:

Yes, that's messy! :biggrin:

Definitely put it in the form of a nice circle (x² + (y-a)² = b²)! :wink:
 

What is a complex number?

A complex number is a number that can be expressed in the form a + bi, where a and b are real numbers and i is the imaginary unit (√-1). It is typically written as z = a + bi.

How do I check the answer to a complex number question?

To check the answer to a complex number question, you can use the rules for complex numbers, such as adding and subtracting real and imaginary parts separately, or using the formula for multiplying complex numbers (FOIL method).

What is the conjugate of a complex number?

The conjugate of a complex number is a number with the same real part, but with an opposite imaginary part. For example, the conjugate of 3 + 4i is 3 - 4i. To find the conjugate of a complex number, you simply change the sign of the imaginary part.

Can a complex number be written in polar form?

Yes, a complex number can be written in polar form as r(cosθ + isinθ), where r is the modulus (or magnitude) of the complex number and θ is the argument (or angle) of the complex number.

How do I divide complex numbers?

To divide complex numbers, you can use the formula (a + bi) / (c + di) = [(ac + bd) / (c^2 + d^2)] + [(bc - ad) / (c^2 + d^2)]i. You can also convert the complex numbers to polar form and use the rule for dividing complex numbers in polar form, which is (r1/r2)[cos(θ1 - θ2) + isin(θ1 - θ2)].

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