How can I determine the order of N in this rate law lab?

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The lab involves determining the order of reactants in the rate law for the reaction between bisulfate and iodate. The rate of disappearance of bisulfate was calculated using the volume and time taken for the blue color change, indicative of the reaction's completion. The order of the reaction with respect to bisulfate was found to be approximately 0.95 after analyzing multiple trials. To find the order with respect to iodate, the user calculated values for N using the same method, ultimately determining an average value of about 3.05. The discussion highlights the process of calculating reaction orders based on varying concentrations in rate law experiments.
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Homework Statement


Hello. I need help with a lab today that involves rate laws.

The goal of this lab is to show the concentration of the reactant ions in this equation

5(HSO3) + 2(IO3) -> I2 + 5(SO4) + H2O + 3H.

We did several trials of varying amounts of the ions and calculated the rate of disappearance of the bisulfate for each trial.

nbdInpN.png


I got the rate of disappearance from taking the volume of the bisulfate and dividing it by the time it took (for the blue color to show, this is supposedly an "iodine clock", thus meaning that the bisulfate had all been used up)

Then I used this formula to calculate the order. I did this for every trial that had the same volume of bisulfate.

This one is using trials 1 and 2.
(20 mL/10 mL)^m (10 mL/10 mL)^n = (.85 mL/s /.46 mL/s)

Sorry if that's hard to read. I did that with trials 1 and 2, 2 and 3, 1 and 3, 1 and 4, and 1 and 5. All the ones that had the same value in my table for the B. That may be confusing. After I did that we averaged the orders of the ones we got. My average order for "m" was 0.95.

But now I am stumped on what to do next. How do I find the value for the order of N so I can find the Rate Law? Is there a way I can find the value of N if none of them are the same for each of the experiments? I cannot seem to be able to find the N because none of the iodate initial concentrations are the same value from experiment to experiment. Some guidance on what to do next would be helpful.

Homework Equations


Rate law

Thank you all for your time, always good help here at physicsforums.
 
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I figured it out. Just plugged in value of M and did it all for the Ns, the average N came out to be about 3.05.
 
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