CHEM QUESTION - answer fast thx alot

  • Thread starter Thread starter xLaser
  • Start date Start date
  • Tags Tags
    Chem
AI Thread Summary
The discussion confirms that the calculation for the pH of 1 M hydrochloric acid is correct, yielding a pH of 0 due to complete dissociation into H3O+ ions. The concentration of H3O+ is also 1 mol/L, matching the concentration of the hydrochloric acid. Participants emphasize that there are no stupid questions in learning, encouraging the original poster. Overall, the calculations and understanding of strong acids are validated. This reinforces the importance of seeking clarification when uncertain.
xLaser
Messages
54
Reaction score
0
:::::: CHEM QUESTION - answer fast please thanks a lot ::::::::

Hi, this maybe a very stupid question but I have a test coming up tomorrow and I'm not sure of this thing here:

Suppose you were given 1 M hydrochloric acid (I assume 1 M to mean a concentration of 1 mol/ L ) Calculate its [H3O]+ (square brackets mean concentratioN) and pH.

ok what did was using pH = - log [H3O]+

then u get -log (1) = 0

there pH =0 , which makes sense since HCl is a very strong acid.

and then apparently the [H3O]+ is 1 mol/L since it was given in the question.

BUT THEN IF IT LIKE THIS, THEN WHAT KIND OF STUPID QUESTION IS THIS? LOL!

I doubt i did this right so can someone please confirm that i did it right or wrong? thanks.
 
Physics news on Phys.org
A strong acid diassociates completely in H_{3}O^{+} or H^{+} so yes the ph will be -log[concentration] and the amount of H_{3}O^{+} or H^{+} will be the HCL concentration.
 


Hi there,

First of all, there is no such thing as a stupid question when it comes to learning. It's great that you are taking the initiative to ask for help and clarification.

You are correct in your calculation for the pH of 1 M hydrochloric acid. As you mentioned, the pH of a strong acid would be 0, since it completely dissociates in water to form H3O+ ions.

In terms of the concentration of H3O+ ions, it would indeed be 1 mol/L since that is the concentration of the hydrochloric acid given in the question. So, you did the calculation correctly.

Keep up the good work and good luck on your test tomorrow!
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top