How does adding a salt of a weak acid to its solution affect the pH?

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Adding a salt of a weak acid to its solution generally creates a buffer system, which helps maintain the pH. The presence of the salt increases the concentration of the conjugate base, shifting the equilibrium and minimizing significant pH changes. However, the actual pH can vary depending on the concentrations of the weak acid and its conjugate base, as described by the Henderson-Hasselbalch equation. If the concentration of the added salt exceeds the buffer capacity, the pH may change. Understanding this concept is crucial for accurately predicting pH behavior in weak acid solutions.
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chem question...curious?!

hi guys i was just wondering that if a solution of a weak acid has a salt of the same acid added to it, what would happen to the pH??

can anyone help me out...thanks in advance
 
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A salt of the same acid? What do you mean?!

-NewScientist
 
well i don't know...it was on my exam that i just had today..and i didnt know how to answer it...thats why I am soo curious...

can anyone please help me out..
 
For example, HCl and NaCl.

I don't believe that a salt will change the pH.
 
anyone else that is more confident
 
Consider acetic acid:

HOAc <=> H+ + OAc-

What would happen to this equilibrium upon increasing the concentration of OAc- say with NaOAc ?
 
And btw welcome to the wonderful world of buffer pairs (which I'm preety sure where this is going) ;)
 
im so lost...i don't know wat the answer was...now I am scared to see my mark...can someone please explain this to me...
 
So - let me get this clear we are talking about a salt that is comprised of :

Metal+(-ve ion from acid) being added to a solution of Hydrgoen+(-ve ion)

At this point, one wuold typically think of displacement, however, the two -ve ions are the same and so i wonder if instead of displacement do we not see a HCl precipitate and NaCl becoming the solution? Just a thought.

-NewScientist
 
  • #10
If HX is a strong acid, then when add HX to water, you will have
HX \rightarrow H^+ + X^-
So after that, if you add NX (a salt) into water. Nothing will happen to the pH. Because all the HX have become H+ And X- (HX is a strong acid). HCl is an example.
---
But if HX is a weak acid, then when add HX to water, you will have
HX \rightleftharpoons H^+ + X^-
So after that, if you add NX (a salt) into water.
NX \rightleftharpoons N^+ + X^-
What can you say about the [X-] at equilibrium state? (It increases).
So what will happen to the H+?
\frac{[H^+] [X^-]}{[HX]} = K_C = const
Viet Dao,
 
  • #11
hi guys i was just wondering that if a solution of a weak acid has a salt of the same acid added to it, what would happen to the pH??
it depends whether the salt is acid salt or normal salt.
Acid besides monobasic acid usually form more than one kind of salts.
That includes hydrogen-containing salt, namely, acid salts.
They dissolve in water to give out hydrogen ions,.
 
  • #12
Dr. Mark has hit the spot, upon adding a certain concentration of the salt, common ion effect will take place and neither of the weak acid or its conjugate salt will contribute to the pH, that is neither the acid will dissociate significantly or the conjugate base act to hydrolyze the water. Thus you will effectively have a buffer solution, the small variations in pH will be due to the autodissociation of water in relation to the equilibrium constant.
 
  • #13
sorry there are soo many answers and you guys are losing me...can someone summarize the correct answer please...thanks again
 
  • #14
The answer is simple...read up on buffers in your chemistry text.
 
  • #15
I don't have my textbook anymore...thats why I am asking up here..I finished school and handed in my textbook..this was a question of my grade 12 chemistry exam...i'm just curious...could someone please help me out...
 
  • #16
Don't you know what a buffer is? Well, again, you would have a buffer solution (upon adding a certain amount of the salt). The pH can be calculated simply by plugging into the henderson-hasselbach equation.
 
  • #17
no i dont...
 
  • #18
A buffer is simply a mixture of a weak acid and its conjugate base or a weak base and its conjugate acid. Buffers work by reacting with any added acid or base to control the pH.

Thus if the salt of the conjugate pair was added to the buffer mixture then there would not be a change in pH due to the fact that the buffers equilibrium will shift to accomadte the addition of the conjugate salt.

Is that clear?
 
  • #19
A buffer is simply a mixture of a weak acid and its conjugate base or a weak base and its conjugate acid. Buffers work by reacting with any added acid or base to control the pH.

Thus if the salt of the conjugate pair was added to the buffer mixture then there would not be a change in pH due to the fact that the buffers equilibrium will shift to accomadte the addition of the conjugate salt.

Is that clear?

actually there would be a change in pH, the pH of a buffer system can vary depending on the ratio of the conjugates. Your explanation of buffers seems adequate enough, if the OP doesn't understand it then he/she needs to refer to a text to get a full explanation instead of sitting around here for an epiphany.

Your original question asks what happens when you add the salt of a weak acid to a weak acid. Explanation...buffers, it's simple as that. If you're asking for an entire tutorial on buffers, well I'll let someone else do that, but you'll get a better and more accurate answers simply by reading a text.
 
  • #20
Well you don't exactly know if the ph will change because your not given any concentration exactly. But if a conjugate salt is added and the the concentration is less then the buffer capacity then the pH will change. You can't just simply say the pH will change. It will only change if the concentration is over buffer capacity
 
  • #21
Observe the henderson hasselbach equation, pH will change, period.

pKa=pH+log \frac{[A-]}{[HA]}, a buffer solution is a mixture of a weak acid and its conjugate salt, buffer capacity pertains to when a strong acid/base is added to the buffer system.
 
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