Chemical Tests for Identifying Sodium Carbonate and Sodium Chloride

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To distinguish between sodium carbonate and sodium chloride, a simple test involves adding hydrochloric acid; sodium carbonate will produce bubbles of carbon dioxide, while sodium chloride will release hydrochloric acid vapors. For identifying aluminum versus platinum, using sulfuric acid will cause aluminum to react visibly, while platinum remains inert. The choice of acid is crucial for both tests, as it affects the reactions observed. The discussion emphasizes the importance of understanding chemical reactions in identifying substances. Overall, these tests highlight the distinct properties of the compounds and metals involved.
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I have just started at university and i have a couple of the questions that i could not fill out during my laboratory.

Lab 1, Acids and Bases

1. Describe a simple chemical test to distinguish between a solid sodium carbonate and solid sodium chloride. My thoughts on this was to react them both with an acid (considering that's what the lab was about, acids and bases). The carbonate would produce water and carbon dioxide, ie. a gas. But i wouldn't know what sodium chloride would do, any help would be great on this one.

2. Describe a simple chemical test to distinguish between a small piece of aluminium and a small piece of platinum. I thought of the acid and or base reacting with them, however i don't know what this would do and how this would help me. Anyone with an idea would be great.
 
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I don't think adding an acid to sodium carbonate would create water and carbon dioxide. Where did the sodium go? That should be included in your chemical reaction. Also, for both question one and two it depends on what kind of acid you are using. Typically metals and nonmetals will combine in a solution.

Huck
 
For both experiments,u need sulphuric acid.


Daniel.
 
For the first,u'd smell the HCl vapors (from the chloride) and see bubbles (from the carbonate).

For the second,u'd see the metal probe "melting",it was Aluminum.

Daniel.
 
thankyou for both of your help, it was greatly appreciated.
 
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