Chemistry) Buffers and Ph differences question

AI Thread Summary
To prepare a buffer with a pH of 4.50 using 100mL of 0.12 mol/L acetic acid and 0.10 mol/L NaOH, the Henderson-Hasselbalch equation is applied to determine the correct ratio of acetic acid to sodium acetate. The addition of NaOH neutralizes acetic acid, forming sodium acetate, which is essential for maintaining the desired pH. To raise the pH to 5.1, a specific volume of 0.20 mol/L NaOH must be calculated based on the new ratio required by the Henderson-Hasselbalch equation. If the same amount of NaOH is added to 250mL of deionized water, the resulting pH can be calculated using the concentration of hydroxide ions produced. Understanding these relationships is crucial for accurately adjusting the pH in buffer solutions.
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Homework Statement



A Chemist wishes to prepare 250mL of buffer that has a Ph of 4.50. Starting with 100mL of 0.12 mol L acetic acid and a supply of 0.10 mol L NaOh.
1) explain how this can be done
3) how much 0.20 molL NaOH must e added to this buffer to raise the pH to 5.1?
3) if the same amount of 0.20 mol L NaOH were added to 250mL of Dionized water, what would the new pH be?

Homework Equations



I know the henderson equation has to be used somewhere but I'm honestly stumped at where to even start :blushing: any general push in the right direction would be seriously appreciated, It's a bonus Lab question, but I'd still like to get any extra marks I could :)
 
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When you add NaOH to the solution of acetic acid, you neutralize it, producing sodium acetate. Just add enough to get a correct ratio given by the HH equation.
 
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