Chemistry Help (on behalf of someone else)

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The discussion focuses on two chemistry problems involving the precipitation of CaF2 and the calculation of enthalpy and temperature for a reaction. For the first problem, the concentration of F- at which CaF2 begins to precipitate can be determined using its Ksp value of 4e-11 in a 0.1 M Ca(NO3)2 solution. The second problem involves calculating the enthalpy of formation for C6H5OH using Hess's law, where the initial calculations led to an incorrect result. Additionally, the temperature at which a nonsponstaneous reaction becomes spontaneous is calculated using the Gibbs free energy equation, with the provided values yielding a discrepancy in the expected temperature. Accurate calculations and careful consideration of all equations are essential for resolving these chemistry questions.
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1) CaF2 is added to a 0.1 M Ca(NO3)2 solution. At what concentration of F- will CaF2 begin to precipitate? Ksp of CaF2 is 4e-11??

2) The solubility of CaF2 (ksp = 4 e-11) in a 0.1 M solution of Ca(NO3)2 is approximately?


Need help finding the solutions for these. I'm posting this for someone else actually who's not that good with using forums. Please be as detailed as you can.

thank you very much in your advance for your help!
 
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You were told at chemical forums that nobody is going to do the question for you. You will do better service to your friend showing her/him how to use forums so that we can guide her/him through the question.
 
Hi I'm very sorry but I copied and pasted the wrong info.

This one has more of an explanation. Let me know if you need anymore info with this.

1) Given the reactions and thermodynamic data below, calculate the enthalphy of formation for C6H5OH kcal/mol.

(kcal)
C6H5OH + 7 O2 --> 6 CO 2 + 3 H2O 729.8
C + O2 ---> CO2 -94.4
2 H2 = O2 ---> 136.8

I used Hess's law and flipped the first equation and got -729.8 kcal and multiplied the second one by 6 to get 566.4 and added everything to get -26.6 kcal.
But this is not the right answer...apparently is +41.7?

2)
The balanced equation below is for a nonsponstaneous reaction (enthalpy of formation = 131 kj/mol and
entropy of formation = 134 J/(mol x k) ). Assuming that the change in enthalpy and entropy do not vary with temperature, at what temperature will the reaction become spontaneous?

C(s) + H2O(l) --->CO(g) + H2(g)

To solve this I used delat G = delta H - T(delta S).
I got 978 K and subtracted it by 273 to get 704 C. However the answer is 1022 C?

Thank you very much for your help.
 
rizwaan said:
I used Hess's law and flipped the first equation and got -729.8 kcal and multiplied the second one by 6 to get 566.4 and added everything

And you have ignored third equation? Show what you got (what reaction equation) after doing what you wrote you did.
 
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