CH4(g) + 3cl2(g) ----> CHCl3(g) + 3HCL(g)
How many grams of CH4 is needed to produce 50.0 g CHCL3 ?
For this problem, I'll assume Carbon = 12 amu, Hydrogen = 1 amu, and CL = 35.5 amu.
The Attempt at a Solution
See the attachment (A PDF file), for my attempt @ the solution.
I think I may have the correct answer; however, I am not positive.
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