Chemistry Problem: Solving with Molar Mass & Isotope Abundance

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To solve the chemistry problem involving molar mass and isotope abundance, the equation for average molar mass can be expressed as x(mass of isotope X) + (1 - x)(mass of isotope Y) = average molar mass. Given the isotopes U-235 and U-238 with respective masses of 235.043924 and 238.050784, the equation becomes x(235.043924) + (1 - x)(238.050784) = 238.0375. Rearranging this equation allows for the calculation of the relative abundance x of U-235. The solution will yield the percentage abundance of each isotope in the element. This method effectively combines molar mass and isotope abundance to find the desired values.
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Hello.
I am doing a chemistry problem but it is mainly mathematics

Here it is.

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A little info that is useful to this problem.

Molar mass is always an average, given by

Molar Mass = (mass of isotope1 * abundance of isotope 1) + (mass of isotope2 + abundance of isotope 2)

Masses of isotopes are always constant, they do not vary from place to place.

So how do I solve this?
 
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While the molar masses do not change, the relative abundances can and do.

An element has isotopes X and Y which have molar masses mx and my with percentage abundances px and py ... rearrange those variables to give an equation for the average molar mass for the element.
 
If we are to assume that the two isotopes given here are the only ones we need consider, then let "x" be the relative abundance of the first (U235) and then the relative abundance of the other (U238) is 1- x.

So we must have x(235.043924)+ (1- x)(238.050784)= 238.0375.

Solve that equation for x.
 
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