Choosing Between the Ordinary & Limit Comparison Test

rcmango
Messages
232
Reaction score
0

Homework Statement



First questions is: How to choose between using the ordinary comparison test, or using the limit comparison test?



Homework Equations





The Attempt at a Solution



then, for these two problems below, i decide to use the limit comparison test:

SUM n_infinity (3n - 2)/(n^3 - 2n^2 + 11) then its said to look for the largest degree of terms in the numerator and denominator and divide through which is to divide by: 3/n^2

but why is 3/n^2 the largest term, when there is a n^3 in there, why not 3/n^3 ?

=======================

also, i see that 1/n belongs to the harmonic series, but what series does 3/n^2 belong to?

thankyou.
 
Physics news on Phys.org
Because the relevant term in the numerator is 3*n. 3*n/n^3=3/n^2.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top