Christoffel Symbols: Intuitive Proof for Covariant Derivative of Metric Tensor

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Discussion Overview

The discussion revolves around the derivation and understanding of Christoffel symbols, particularly in relation to the covariant derivative of the metric tensor. Participants are exploring intuitive proofs and references that clarify this concept, focusing on both theoretical and practical implications.

Discussion Character

  • Exploratory, Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant expresses frustration with the standard derivation of Christoffel symbols, describing it as lacking physical intuition and seeking a more intuitive proof based on the covariant derivative of the metric tensor being zero.
  • Another participant suggests consulting chapter 3 of Wald's General Relativity book for insights on the topic.
  • A different participant recommends "Riemannian Manifolds: An Introduction to Curvature" by John Lee as a resource, although they do not recall specific details regarding the proof.
  • One participant clarifies that the ordinary derivative of a tensor is not a tensor itself, and emphasizes that the Christoffel symbols are necessary to convert it into a covariant derivative.
  • A later reply mentions that an outline solution for an intuitive proof can be found in MTW exercise 8.15.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on a specific intuitive proof for the covariant derivative of the metric tensor. Multiple references and approaches are suggested, indicating a variety of perspectives on the topic.

Contextual Notes

Some participants reference specific texts and exercises that may contain relevant information, but the discussion does not resolve the underlying question of finding a more intuitive proof.

zwoodrow
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I am learning about christoffel symbols and there is a pretty standard representation of christoffel symbols as a linear combination of products of the metric tensor and the metric tensors derivative. However when this is derived it is always done in a hoakey manner. Something along the lines of ... do these permutations add this subtract that and walllaaa. I am trying to make a more physically intuitive proof based off the covariant derivative of the metric tensor being equal to zero. Has anyone seen this proof somewhere i haven't got it to work out and i am looking go help.
 
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Check out chapter 3 of Wald's GR book.
 
I think the best place to read about connections is "Riemannian manifolds: an introduction to curvature", by John Lee. But I don't remember how he did this particular thing.
 
The ordinary derivative of a tensor is NOT a tensor. In order to make it one, the "covariant derivative", you have to subtract off the Christoffel symbols- or, to put it another way, the Chrisoffel symbols are the covariant derivative minus the ordinary derivative.
 
zwoodrow said:
I am trying to make a more physically intuitive proof based off the covariant derivative of the metric tensor being equal to zero. Has anyone seen this proof somewhere i haven't got it to work out and i am looking go help.

Yes, you can find it in MTW exercise 8.15. It has an outline solution too.
 

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