Find the center and radius of the circle(adsbygoogle = window.adsbygoogle || []).push({});

16x^2 + 16y^2 + 8x + 32y + 1 = 0

So first i simplified the equation by taking out the 16

so i got:

16 (x^2 + 1/2x + y^2 + 2y) = -1

16 (x^2 + 1/2x + 1/16) + 16 (y^2 + 2y + 1) = -1 + 1 + 1

16 (x + 1/4)^2 + 16 (y + 1)^2 = 1

Center = (-1/4, -1)

Radius = 1

Are my calculations correct? Do I need to take out the 16 in my equation?

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# Circle eqauation - can ne1 double check my work

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