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## Homework Statement

Find Vx using source transformation

## Homework Equations

V=IR

KVL

## The Attempt at a Solution

After doing source transformation on the three pairs of current sources and resistors...

KVL:

-6+2I-Vx+4I-3+3I+5I-2=0

14I-Vx-11=0

but Vx=5I (is it? i'm not so sure about this)

14I-5I-11=0

1I=11

I=1.222 A

Vx=-5I=-5(1.222)

**Vx=-6.11 V**

Did I do the source transformation right? Also, I'm confused with the value of Vx. Is it -5I or just 5I? Because in our class, our convention is that when a current source is transformed into a voltage source, the part where the arrow head in the current source becomes the positive terminal for the voltage source. But since we're only dealing with a resistor here, I just followed our convention for the KVL (the voltage across 5 ohms is positive since the mesh current enters the positive terminal)

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