Circuit Analysis: Understand V2 & 3amp Equation

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Discussion Overview

The discussion revolves around understanding a circuit analysis problem, specifically focusing on the voltage V2 and the current of 3 amps. Participants are exploring the application of Kirchhoff's Current Law (KCL) to derive the relevant equations and clarify the relationships between current and voltage in the circuit.

Discussion Character

  • Exploratory, Technical explanation, Homework-related

Main Points Raised

  • One participant expresses difficulty in understanding how V2 equals 6 volts and the origin of the 3 amps that contribute to this voltage.
  • Another participant suggests using KCL to find the current through a specific part of the circuit, indicating that this could aid in understanding the current through the 2Ω resistor.
  • A participant acknowledges that the total current is the sum of currents through two resistors, suggesting a straightforward approach to the problem.
  • There is a request for help in formulating the linear equation that results in the 3 amps, indicating a need for clarification on this aspect.
  • One participant provides a KCL equation for a junction, stating that the currents add up to 3 amps, but questions remain about the participant's understanding of this equation.

Areas of Agreement / Disagreement

The discussion reflects a lack of consensus, with participants expressing different levels of understanding and clarity regarding the application of KCL and the derivation of the current equation.

Contextual Notes

Participants have not fully resolved the assumptions or steps needed to derive the linear equation for the current, and there are indications of varying interpretations of the circuit's behavior.

fran1942
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Hello, I have tried really hard to understand this circuit but I just can't grasp it.

I am trying to understand how V2 comes to 6 volts ie. where does the 3amp come from that is multiplied by the value of V2 to give 6 volts.
It would help a lot if I could see the linear equation which gives 3 amps for the relevant loop.

Thanks kindly for any help with this.
 

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hello fran1942! :smile:

use KCL to find the current through the bottom wire, directly under the 2Ω …

how much is that, and how does it help you to find the current through the 2Ω itself? :wink:
 
OK thanks. I see that current will be the combination of the 2 and the 1, making 3. Is it as simple as that ?

The main thing bugging me was that I could not work out the linear equation to give that 3amps.
Could someone please help with that equation.

Thanks again.
 
fran1942 said:
… I could not work out the linear equation to give that 3amps.

not following you …

the KCL linear equation for that junction under I2 is 1 + 2 = 3 …

what is worrying you about that? :confused:
 

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