Engineering Circuit Analysis: Understand V2 & 3amp Equation

AI Thread Summary
Understanding the circuit involves applying Kirchhoff's Current Law (KCL) to determine the current through the components. The discussion highlights that the current through the 2Ω resistor is a combination of the currents from the 1Ω and 2Ω resistors, totaling 3 amps. The key equation derived from KCL at the junction is I1 + I2 = 3 amps. The user seeks clarity on how this leads to a voltage of 6 volts for V2. The conversation emphasizes the importance of grasping these foundational concepts in circuit analysis.
fran1942
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Hello, I have tried really hard to understand this circuit but I just can't grasp it.

I am trying to understand how V2 comes to 6 volts ie. where does the 3amp come from that is multiplied by the value of V2 to give 6 volts.
It would help a lot if I could see the linear equation which gives 3 amps for the relevant loop.

Thanks kindly for any help with this.
 

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hello fran1942! :smile:

use KCL to find the current through the bottom wire, directly under the 2Ω …

how much is that, and how does it help you to find the current through the 2Ω itself? :wink:
 
OK thanks. I see that current will be the combination of the 2 and the 1, making 3. Is it as simple as that ?

The main thing bugging me was that I could not work out the linear equation to give that 3amps.
Could someone please help with that equation.

Thanks again.
 
fran1942 said:
… I could not work out the linear equation to give that 3amps.

not following you …

the KCL linear equation for that junction under I2 is 1 + 2 = 3 …

what is worrying you about that? :confused:​
 

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