Circuits 1 help with integration

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
sammyqw
Messages
20
Reaction score
0

Homework Statement



http://imgur.com/a/qlQ5z
jJjYb53.png


Homework Equations



i=i(o)+1/L integration(v0) dt formula is in the attemp at a solution.

The Attempt at a Solution


http://imgur.com/a/HVjl1
For the interval 2<t<infinite . I understand that voltage at 2ms is 0 , but where did they get 2x10^-3? is that the 2ms to seconds? and how did they 50ma after the integration? I only get 10ma not 50. Thanks in advance.
 
Physics news on Phys.org
Nevermind I think I got it. After getting 25t we do i(0.002seconds)=25(0.002)= 0.05a then for the interval 2<t<infinity i= i (0) +1/L... substituting i(o) is 0.05a so i=0.05 + integration of 0 which is 0= so the final answer is 0.05a :o
 
Looks correct to me. I checked it this way..

V = Ldi/dt
so
di/dt = V/L
= 5*10-3/200*10-6
=25 amps per second (or 25t if you prefer)

Calculate I after 2mS..
25*2*10-3 = 0.05A