Circular accelaration with increasing velocity?

AI Thread Summary
The discussion centers on calculating the force applied to an object moving along a circular arc with increasing velocity. The object starts from rest, accelerates along a 45-degree arc with a radius of 2 meters, and reaches a speed of 7 m/s before release. The total force required combines centripetal force, which acts radially inward, and tangential force, which increases the object's speed. The radial unit vector, represented as {Rho}, indicates the direction of the centripetal force, while the tangential force is necessary for acceleration along the arc. Understanding these forces is crucial for solving the problem accurately.
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circular accelaration with increasing velocity?

Homework Statement


Object starts at rest at an angle of 0 degree's. the object is accelerated along a 45 degree arc with a radius of 2 meters to a speed of 7m/s at which point it is released. the object has a mass of .3 Kg. What is the equation for the force applied along the arc?


Homework Equations



circular accel. = V[2][/r] and other kinematics and derivatives and anti-derivatives

The Attempt at a Solution


way more work than i am going to put on here, but in the end i got a jerk function of 960.4/pi
... not fun
 
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To keep it in a circle you need a certain force. To accelerate it tangentially you need another. Superpose them to get the total force.

\vec{F}=-\frac{mv^{2}}{R}\hat{\rho}+F_{tan}\hat{\theta}

Then use basic kinematic equations with the information given to find the tangential force. Then it's just a matter of getting the magnitude, which we expect to be time dependent due to the centripetal contribution.
 


just a couple questions on that ... what does the {Rho} represent and why is it Ftan?
 


The rho is the radial unit vector. Centrifugal forces push the mass out; in order for it to stay in a circle there needs to be an equal and opposite force pulling it in. This is what the force in the negative rho direction represents.

Mathematically,

\hat{\rho}=cos(\theta)\hat{x}+sin(\theta)\hat{y}

As for the other component of the force it is directed tangentially to the circle because it increases the tangential speed of the mass.
 
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