Circular disk rotates with student on it

AI Thread Summary
A circular disk platform with a mass of 150 kg and a radius of 2.00 m rotates on a frictionless bearing, with a student weighing 60 kg walking toward the center. The initial angular speed is 1.5 rad/s, and the discussion revolves around calculating the new angular speed when the student is 0.50 m from the center. The initial calculation of rotational inertia was incorrect, as it mistakenly combined the masses instead of their respective moments of inertia. As the student moves inward, the system's rotational inertia decreases, which can lead to an increase in angular speed, similar to figure skaters pulling in their arms. Correctly calculating the initial inertia is crucial for determining the final angular speed accurately.
bearhug
Messages
78
Reaction score
0
A horizontal platform in the shape of a uniform circular disk rotates on a frictionless bearing about a vertical axle through the center of the disk. The platform has a mass of 150 kg, and radius of 2.00 m. A 60kg student walks slowly from the rim of the platform toward the center. If the angular speed of the system is 1.5 rad/s when the student starts walking, what is the angular speed when she is 0.50 m from the center?

I originally used the equation Li=Lf
where Li= Iw= (1/2)(MR^2)wi which equals (.5)(210kg)(2.0^2)(1.5rad/s)
Li= 630
Lf= (If1+ If2)(wf)
=[(.5)(150)(2.0^2) + (60)(0.5^2)]wf
This gave me wf= 2.0 rad/s but that doesn't seem to make sense wouldn't the angular speed slow down as the student went closer to the center? Any hints as to where I went wrong is greatly appreciated.
 
Physics news on Phys.org
Angular velocity wouldn't necessarily slow down as you go towards the center. Ever watch figure skating where a skater starts a spin with his legs/arms extended and as he brings his arms/legs closer he begins to spin much quicker? Ever watch divers do multiple flips, they bring as much mass as possible close to their axis of rotation to spin fast then when they want to stop they extend their arms and legs to finish the dive.
 
bearhug said:
I originally used the equation Li=Lf
where Li= Iw= (1/2)(MR^2)wi which equals (.5)(210kg)(2.0^2)(1.5rad/s)
You have computed the wrong initial value for I of the system, which will give you a wrong value for Li.
Li= 630
Lf= (If1+ If2)(wf)
=[(.5)(150)(2.0^2) + (60)(0.5^2)]wf
This time you computed the final rotational inertia properly. (Fix your initial value accordingly.)
This gave me wf= 2.0 rad/s but that doesn't seem to make sense wouldn't the angular speed slow down as the student went closer to the center?
What happens to the rotational inertia of the system as the person moves closer to the center? (Does it increase or decrease?) Then consider that L = Iiwi = Ifwf.
 
Thanks for the advice. Since only the initial value is incorrect I am under the impression that it is the Mass that is wrong. Originally I included both the student and the platform in the mass because I interpreted the problem as the student already being on the platform at the beginning. However that doesn't seem to be giving me the correct initial. So is that because the student isn't actually on the platform in the beginning? Thanks
 
The student is on the platform from the beginning. For some reason, when calculating the intial rotational inertia of the system you just added the masses instead of adding the rotational inertias of disk and student.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top