Circular loop problem: finding the radius of a small circle

Benzoate
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Homework Statement



In an air show, a pilot is to execute a circular loop at the speed of sound(340 m/s) . The pilot may black out if his acceleration exceeds 8g. Find the radius of the smallest circle he can use. [Take g=10 m s^-2

Homework Equations



possible equations: u^2 >= 2*M*G/a
m*dv/dt=-m*M*G/r^2
m*v^2/r=-m*M*G/r^2

The Attempt at a Solution



u=340 m/s
a=dv/dt=>=80 m s^-2
M=6.00e24 kg
G=6.67e-11

acceleration=dv/dt=> dv/dt=-M*G/r^2

option one
r=sqrt(M*G/(dv/dt)=7.07e12 meters
option 2
a=2*M*G/u^2, a being minimal radius and not the acceleration

a= 28284271.25 meters

actual answer: r>=1445 meters

what did I do wrong? should I have used polar coordinates since the problem states that the plane is going around a loop?

Perhaps I should write:

m*dv/dt=F(z) , F(z) representing the sum of all forces. the only two forces acting on the object is the gravitational force and the centripetal force ; so my equation looks like:

m*dv/dt=m*v^2/r-m*g

dv/dt=dv/dr*dr/dt=dv/dr*v. Now I can integrate in terms of the velocity vector and radius vector.

dv/dr=v^2/r-g

I get something that looks like this:

dv/v=dr/r-dr/g ==> ln v = In r -r/g
 
Last edited:
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Hi,

What equations do you know of that deal with circular motion?

FYI, the "r" in m*M*G/r^2 is not necessarily a radius, it's the distance between two masses.
 
Redbelly98 said:
Hi,

What equations do you know of that deal with circular motion?
hi,

the equations that deal with circular motion are : F(centripetal)=m*v^2/r and the equation for a particle in general motion:
FYI, the "r" in m*M*G/r^2 is not necessarily a radius, it's the distance between two masses.

Well, since the airplane is obviously flying around a circle on earth, then doesn't the radius of the Earth , plus the height the airplane is some distance above the surface of the Earth become relevant in finding the total R=R(earth)+height?
 
Benzoate said:
In an air show, a pilot is to execute a circular loop at the speed of sound(340 m/s) . The pilot may black out if his acceleration exceeds 8g. Find the radius of the smallest circle he can use. [Take g=10 m s^-2

M=6.00e24 kg
G=6.67e-11

Hi Benzoate! :smile:

I'm really confused :confused:

the question gives you the acceleration (8g) … which you can assume is constant (they're telling you g = 10, which is about 2% out anyway :wink:)

you don't need G or M!

Try again (and don't forget you'll have to add or subtract up to 1g for the gravity) :smile:
 
tiny-tim said:
Hi Benzoate! :smile:

I'm really confused :confused:

the question gives you the acceleration (8g) … which you can assume is constant (they're telling you g = 10, which is about 2% out anyway :wink:)

you don't need G or M!

Try again (and don't forget you'll have to add or subtract up to 1g for the gravity) :smile:

could I just write:

a=v^2/r and since I know v and a I can easily calculate r correct?
 
Benzoate said:
could I just write:

a=v^2/r and since I know v and a I can easily calculate r correct?

:biggrin: Woohoo! :biggrin:
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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