Circular Motion, and Conservation of Energy problem

AI Thread Summary
The discussion focuses on deriving the speed of a ball in vertical circular motion and determining the minimum speed required to maintain that motion. For part (a), the derived expression for speed v at any angle theta is v = √[v(o)² + 2gRsin(theta)]. For part (b), the minimum speed v(o) must be at least √[2gRsin(theta)] to ensure the expression inside the square root remains positive. The calculations highlight the relationship between gravitational force, radius, and speed in circular motion. Understanding these principles is crucial for solving problems related to conservation of energy in circular dynamics.
leighzer
Messages
10
Reaction score
0
A ball of mass m is spun in a vertical circle having radius R. The ball has a speed v(o) at its highest point. Take zero potential energy at the lowest point, and use the angle theta measured with respect to the vertical.

(a) Derive an expression for the speed v at any time as a function of R, theta, v(o), and g.
(b) What minimum speed v(o) is required to keep the ball moving in a circle?


I found part (a) to be:

v = *square root*[ v(o)^2 + 2gRsin(theta) ]


I'm not totally sure if this is correct, and i don't know how to find the minimum value of v(o).


Is someone able to help?
 
Last edited:
Physics news on Phys.org
The only thing I can think of for part (b) is that v(o) must be greater than or equal to:

-*sqr rt*[ 2gRsin(theta) ]

in order to keep the value inside the square root of the first equation positive.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top