Circular Motion and Newton's Laws

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A model airplane with a mass of 7.50 kg flies in a horizontal circle at a speed of 35 m/s, controlled by a 60.0 m wire, with aerodynamic lift acting at a 20-degree angle West of North. The forces acting on the plane include weight, tension, and aerodynamic lift, with tension at an angle of 20 degrees South of East. The scalar equations for the forces are Fx = -Tcos(20) - Fsin(20) = mv^2/r and Fy = -Tsin(20) + Fcos(20) - mg = 0. The correct tension value needed to maintain circular motion is 12.8 N. Further assistance is encouraged in the homework help section for clarity on the setup.
rmarkatos
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A model airplane of mass 7.50 with a speed 35m/s flies in a horizontal circle at the end of 60.0m control wire. Aerodynamic lift acts on the plane at an angle of 20 degrees West of North.

In the picture the book has the plane on the right. The weight is acting straight down, the tension is acting at angle of 20 degrees South of East and the aerodynamic lift is acting 20 degrees west of north.

Can someone set up the x and y scalar equations please. The answer is 12.8N. I have set it up 5 different ways and i can't seem to get the right answer.
 
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You should show some work and post it in the homework help section next time. Now if you'll excuse me, I got to jet.

~Ciao
 
Looks like this was moved to homework help, but rmarkatos had already posted there.

May be best to continue in the other thread.
 
Fx -Tcos20 - Fsin20 = mv^2/r
Fy -Tsin20 + Fcos20 - mg = 0 where T is the tension and F is the aerodynamic lift

Those are the equations based on the picture described.
 
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