# Circular motion involving friction and tension

#### fighter2_40

1. The problem statement, all variables and given/known data
There is a block on a turntable. It is attached to the center of the table by a string with the length .4m. Also the static friction constant between the table and the block is 0.8 .
If the maximum tension the string can support is 300n how fast can the table spin without the string snapping? 2. Relevant equations
mass (velocity)^2 / radius = Centripetal Force
mass x 9.8 [gravity] x U [friction constant] = Force of Friction

3. The attempt at a solution

mv^2/.4 = 300 + .8mg

V = sqr(120/m +3.136)

Where do I go from here? Can I find a quantitative value for velocity if the mass of the block is not given?

Thanks! I would appreciate it if I can get an answer tonight. My impression is that this is due tomorrow.

Related Introductory Physics Homework News on Phys.org

#### rl.bhat

Homework Helper
The block is accelerating towards the center of the turntable. So the frictional force on the turntable is away from the center. Reaction to this frictional force on the block is towards the center.
Now rewrite the equation.

#### fighter2_40

rl, i'm not sure I follow. I understand that the block is accelerating towards the center. Aren't i only concerned with the friction force on the block, which is towards the center (this is part of the forces necessary for allowing the block not to move to a farther orbit).

What I don't understand is why my equation mv^2/r = Ftension + Ffriction towards the center is incorrect. Further I don't know how to solve this without a given mass. Perhaps my teacher had forgotten to give the mass.

#### rl.bhat

Homework Helper
You are right. Mass must be given to solve the problem.

### Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving