Circular Motion: Net Force, Speed & Direction at Top - M,L,g

AI Thread Summary
At the top of a vertical circular path, the tension in the string is twice the weight of the mass M, leading to a net force equation of F_net = T + mg. This results in F_net being expressed as 3mg, with the direction of the net force directed towards the center of the circle, or downwards. The speed of the ball at this point can be calculated as v = √(3gL). The analysis confirms that the net force and velocity are dependent on the mass, gravitational acceleration, and the length of the string. Overall, the key takeaway is that both the net force and speed can be expressed in terms of M, g, and L, with the net force directed towards the center of the circular path.
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A mass M attached to a string of length L moves in a circle in a vertical plane.AT the top of the circular path, the tension in the string is twice the weight of the ball.
--find magnitude and direct of Net force and speed of the ball at the top.Express aswer in term of M,L,g

net force= T-mg = mv^2/L
2mg-mg = mv^2L
F=Square root gL

F=mv^2/L
Square root gL=mv^2L
Square root of( (L*square root Lg)/m )
 
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They want the magnitude and direction of the net force in terms in terms of m, g and L... so v shouldn't be in your answer...

When the ball is at the top of the loop T and mg are in the same direction:

Fnet = T + mg = mv^2/L

so what is Fnet in terms of m and g... what is the direction of Fnet. What is v in terms of m, g and L...
 
Fnet = T + mg
2mg+mg=3mg , the direction for Fnet is toward the center? not sure

3mg=mv^2/L
L3mg=mv^2 m cancel
v= Square root of 3Lg, the direction for velocity is horizontal and tangentially to the circle, to the right
 
yes, v=sqrt(3Lg) looks right to me. Yes, direction of Fnet is towards the center... in other words downwards since the mass is at the top of the circular path.
 
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