Rock's Angular Motion in Bicycle Wheel Braking

AI Thread Summary
A rock embedded in a bicycle wheel with a diameter of 53.0 cm has a tangential speed of 3.50 m/s and experiences a tangential deceleration of 1.20 m/s² when brakes are applied. The calculations for angular velocity (omega) and angular acceleration (alpha) are discussed, with initial attempts yielding incorrect results due to unit or significant figure errors. The correct approach involves using the relationship between tangential speed and radius to find omega and applying the angular acceleration formula. The conversation emphasizes the importance of using radians for angular measurements. Overall, the thread explores the physics of angular motion in the context of braking dynamics.
freak_boy186
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Homework Statement


A rock stuck in the tread of a 53.0 cm diameter bicycle wheel has a tangential speed of 3.50 m/s. When the brakes are applied, the rock's tangential deceleration is 1.20 m/s^2.

X.) What is the magnitudes of the rock's angular velocity (omega) when t = 1.60s?
Y.) What is the magnitudes of the rock's angular acceleration (alpha) when t = 1.60s?
Z.) At what time is the magnitude of the rock's acceleration equal to g? (9.8 m/s^2)

Homework Equations


v = r(omega)
a = r(omega)^2
Vf = Vi + a[tangental](dt)
D[omega] = alpha(dt)
omega^2 = omega0^2 + 2(alpha)(dtheta)

The Attempt at a Solution


X.) r = 0.265m, a[tangental] = -1.2, Vi = 3.5, dt = 1.6
Vf = 3.5 + (-1.2)(1.6) = 1.58
omega = 1.58/0.265 = 5.962 {incorrect apparently}

Y.) omega1 = 3.5/.265 = 13.208
(13.208 - 5.962) = alpha(1.6)
alpha = 4.528 {incorrect, but expected because X is incorrect}
 
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freak_boy186 said:

Homework Statement


A rock stuck in the tread of a 53.0 cm diameter bicycle wheel has a tangential speed of 3.50 m/s. When the brakes are applied, the rock's tangential deceleration is 1.20 m/s^2.

X.) What is the magnitudes of the rock's angular velocity (omega) when t = 1.60s?
Y.) What is the magnitudes of the rock's angular acceleration (alpha) when t = 1.60s?
Z.) At what time is the magnitude of the rock's acceleration equal to g? (9.8 m/s^2)

Homework Equations


v = r(omega)
a = r(omega)^2
Vf = Vi + a[tangental](dt)
D[omega] = alpha(dt)
omega^2 = omega0^2 + 2(alpha)(dtheta)

The Attempt at a Solution


X.) r = 0.265m, a[tangental] = -1.2, Vi = 3.5, dt = 1.6
Vf = 3.5 + (-1.2)(1.6) = 1.58
omega = 1.58/0.265 = 5.962 {incorrect apparently}
That's correct. Maybe you're not entering it in the right units or with the correct number of significant figures.
Y.) omega1 = 3.5/.265 = 13.208
(13.208 - 5.962) = alpha(1.6)
alpha = 4.528 {incorrect, but expected because X is incorrect}
That's correct too, although you took a roundabout way of calculating it.
 
its asking for omega in rad/sec & alpha in rad/sec^2... would that affect my answers any?
 
Nope. Radians is the natural unit for measuring angles.
 
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