Circular Motion - Wall of death Problem

AI Thread Summary
The discussion focuses on calculating the minimum and maximum speeds for a motorcycle on a wall of death scenario. The minimum speed required to keep the rider on the wall is determined to be 6.26 m/s, based on the coefficient of friction and radius. For the maximum speed, considering a maximum gravitational force of 4 g, the calculations yield a speed of 12.5 m/s. The participants clarify the relationship between radial force and speed, leading to the final confirmation of the maximum speed calculation. Overall, the problem emphasizes the importance of understanding forces in circular motion.
blackbird2552
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Homework Statement




Total mass = 260 kg
Coefficient of Friction = 1.00
r = 4 m
gmax = 4 g

a) Find the minimum speed to keep the rider on the wall of death.

b) Find the maximum speed inside the wall of death of the motorcycle based on gmax




Homework Equations




\mu x (mv^2/r) = mg
Fc = mv^2/r
Gforce = mv^2/r


The Attempt at a Solution



a)

V = \sqrt{ g r / \mu}

V = 6.26 m/s

b)

Gforce = mv2/r

4 = 0.26g x v2 / 4 m
V = 7.84 m/s

I don't know if it is right...
 
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blackbird2552 said:

Homework Statement

Total mass = 260 kg
Coefficient of Friction = 1.00
r = 4 m
gmax = 4 g

a) Find the minimum speed to keep the rider on the wall of death.
Correct.

b) Find the maximum speed inside the wall of death of the motorcycle based on gmaxGforce = mv2/r

4 = 0.26g x v2 / 4 m
V = 7.84 m/s

I don't know if it is right...
I can't follow your reasoning. What is the maximum radial (normal to the wall) force (in Newtons)? What is the relationship between that force and the speed of the motorcycle? What is the motorcycle speed needed to achieve that force?

AM
 
..what i need to do is find is the maximum speed at which the motorcycle should be going to get the max value of g, that is 4 gs...i don't get how i will calculate it!...what i did is, since Fc = mv^2/r...the gforce = mv^2/r., i had the mass and the radius...i solved it for v...i think i should convert the 4 g to the force in Newton that would be the maximum radial (normal to the wall) force (in Newtons)...i don't know how to do that...help?...
 
i think i got where i went wrong in the second one

The total force acting when the mass is experiencing 4 gs is

4g = 39.24 m/s2
F = ma
F = 260 kg x 39.24 m/s2 = 10202.4 N

to get the max v

Fc = mv2/r

10202.4 = 260kg x v2 / 4 m
V = underoot 156.96
V = 12.5 m/s

Is this right??...
 
blackbird2552 said:
i think i got where i went wrong in the second one

The total force acting when the mass is experiencing 4 gs is

4g = 39.24 m/s2
F = ma
F = 260 kg x 39.24 m/s2 = 10202.4 N

to get the max v

Fc = mv2/r

10202.4 = 260kg x v2 / 4 m
V = underoot 156.96
V = 12.5 m/s

Is this right??...
Correct.

AM
 
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