Circular Movement Homework: Part A Done, Part B Troubles

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The discussion revolves around solving a homework problem related to circular motion, specifically finding tension as a function of angle. Participants emphasize the importance of expressing velocity as a function of angle and suggest using energy conservation principles to relate potential and kinetic energy. The student expresses confusion about the changing velocity and the role of tension, leading to clarification that tension does not perform work on the ball due to its perpendicular orientation to the motion. Overall, the conversation highlights the need to apply energy concepts and the correct equations to solve the problem effectively. Understanding these principles is crucial for completing the homework successfully.
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Homework Statement



Everything is in the pictures.
I did part A, I have a problem with part B.
10x in advance.

Homework Equations





The Attempt at a Solution

 

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You need to find the tension as a function of angle. (Forget the tension at the top.)

You have the correct equation. Hint: Express v^2 as a function of angle.
 
Doc Al said:
You need to find the tension as a function of angle. (Forget the tension at the top.)

You have the correct equation. Hint: Express v^2 as a function of angle.

I know this equation (in the pic) but I'm doubtful if this what you meant...

Should I use trigo? can I get another tip :smile:?

10x.
 

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The equation I had in mind was: mv^2/r = T + mg cos(theta).

Another hint: What's conserved as the ball continues on its path?
 
Doc Al said:
The equation I had in mind was: mv^2/r = T + mg cos(theta).

Another hint: What's conserved as the ball continues on its path?

Ok, I already wrote that equation at the beginning in the solution part I uploaded and got stuck there.

I got stuck because I don't know the velocity at this point, I mean, the velocity is not constant, right? there is a mgsin(theta) that keep changing it...I think.

The velocity at the top is not the velocity at the bottom, right?

10x.
 
asi123 said:
I got stuck because I don't know the velocity at this point, I mean, the velocity is not constant, right?
The velocity is definitely not constant. Reread my hint in post #4. :wink:

Given the velocity at the top, you should be able to find the velocity at any point as a function of angle.
 
Doc Al said:
The velocity is definitely not constant. Reread my hint in post #4. :wink:

Given the velocity at the top, you should be able to find the velocity at any point as a function of angle.

:confused: I'm totally stuck, should I use trigo, or there is some equation for the velocity that I don't know about...

Oh, maybe u mean to use energy calculation?
 
asi123 said:
Oh, maybe u mean to use energy calculation?
Getting warmer! :smile:
 
Doc Al said:
Getting warmer! :smile:

The potential energy turns into kinetic energy, no?
 
  • #10
You got it. Keep going.
 
  • #11
Ok, I haven't really learned Conservation of energy so I'm not really familiar with it...

I wrote this equation about the energy, is it correct?

And another thing, What about T? it's not a Conservative force, right? Do I just ignore it in the the energy equation?

10x.
 

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  • #12
asi123 said:
Ok, I haven't really learned Conservation of energy so I'm not really familiar with it...

I wrote this equation about the energy, is it correct?
Looks good to me.
And another thing, What about T? it's not a Conservative force, right? Do I just ignore it in the the energy equation?
Excellent question! Ask yourself: Does the tension force do any work on the ball?
 
  • #13
Doc Al said:
Looks good to me.

Excellent question! Ask yourself: Does the tension force do any work on the ball?

Oh, right, it's vertical to his movement.

10x a lot.
 
  • #14
The ball's movement is always perpendicular to the tension, thus the tension does no work on the ball.
 
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