- #1

Dr.AbeNikIanEdL

Gold Member

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[itex] |K_1> = \frac{1}{\sqrt{2}}(|K^0> - |\bar{K^0}) [/itex]

[itex] |K_2> = \frac{1}{\sqrt{2}}(|K^0> + |\bar{K^0}) [/itex]

and, assuming CP conservation, the only possible decay modes should be

[itex] K_1 \rightarrow 2\pi[/itex]

[itex] K_2 \rightarrow 3\pi[/itex]

In the footnote at the end of the page (146) it is mentioned that "with the right combination of orbital angular momentum, it is possible to construct a ## CP=+1## state of the [##3\pi##] system, [...] this might allow ##K_1## to decay (rarely) into ##3\pi## [...]".

Now my question is, as Kaons as well as pions have spin 0, wouldn't angular momentum conservation forbid any orbital angular momentum in the final state? Do I miss something or is ##K_1 \rightarrow 3\pi## then rigorously forbidden (under the assumption of strikt CP conservation)?