Clarification : S = K ln W and S = K ln omega

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Discussion Overview

The discussion centers on the relationship between the entropy formulas S = K ln W and S = K ln Ω, exploring their definitions and implications in both equilibrium and non-equilibrium states. Participants examine the meanings of W and Ω, their roles in statistical mechanics, and the conditions under which these expressions are valid.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants propose that W represents the probability of a system being in a particular state relative to all other possible states, while Ω is associated with maximum entropy in equilibrium.
  • Others argue that W and Ω are simply different symbols representing the multiplicity of the corresponding macrostate, and that they are not probabilities.
  • One participant questions whether the definition of entropy remains valid for non-equilibrium states, referencing the challenges in defining entropy at a specific moment for such systems.
  • A later reply discusses a progression from S = k ln W to S = k ln Ω, suggesting that while both denote microstates, they are not interchangeable.
  • Another participant expresses confusion regarding the derivation of S = k ln Ω from S = k ln W, particularly in the context of uniform and non-uniform probability distributions.
  • There is a question about whether the equation S = K ln Ω is only applicable in equilibrium conditions.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the differences or similarities between W and Ω, and the discussion remains unresolved regarding the applicability of these formulas in non-equilibrium states.

Contextual Notes

Some limitations are noted regarding the definition of entropy in non-equilibrium systems, including the difficulty in establishing a clear definition at a specific moment in time and the conditions under which these definitions hold.

Point Conception
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With S = K ln W where W is probability system is in the state it is in relative to all other possible states :
W = VN , V = volume, N = number of particles so ln W = N (ln V)
And this expression is for non equilibrium state.
For equilibrium state S = K ln Ω Then is the only difference between W and Ω that Ω is for maximum entropy ?
If so it appears it would have same value as W
 
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As far as a know, there is no difference in that equation between W and Ω; it is simply a different choice of symbol.

W or Ω represent the multiplicity of the corresponding macrostate. It is not a probability. (It couldn't be, because a probability ≤ 1, so S would be negative or 0, but entropy is always a positive quantity.)

Calculating entropy for a non-equilibrium system is not a trivial thing.
 
But the definition is still valid, even for a non-equilibrium state?
 
Chandra Prayaga said:
But the definition is still valid, even for a non-equilibrium state?
From https://en.wikipedia.org/wiki/Non-equilibrium_thermodynamics
Wikipedia said:
Another fundamental and very important difference is the difficulty or impossibility, in general, in defining entropy at an instant of time in macroscopic terms for systems not in thermodynamic equilibrium; it can be done, to useful approximation, only in carefully chosen special cases, namely those that are throughout in local thermodynamic equilibrium.[1][2]

See also https://physics.stackexchange.com/questions/134377/definition-of-entropy-in-nonequilibrium-states
 
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My confusion here is that omega is used to derive S = k ln Ω :
1) S = k ln W where W = (V)N microstates
This leads to the Gibbs statistical entropy formula for non uniform probability distribution, non equilibrium systems :
2) S = - k ∑ pi ln pi
Then in special case of uniform distribution pi = 1/Ω
3) S = -k Σ 1/Ω ln 1/Ω = k ln Ω
For maximum entropy equilibrium systems
It would help to resolve omega and W if pi = 1/W for uniform distribution
 
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Does S = K ln Ω only hold in equilibrium?
 
From link in post #5
Screenshot_2022-03-24-19-38-36-65.jpg
 
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