Classical Mechanics - Statics - Mass and overhang

AI Thread Summary
The discussion revolves around a physics problem involving a block under an overhang at an angle θ, with a horizontal force applied. Key points include creating a free-body diagram to identify forces acting on the block, calculating the normal force and friction force, and determining the maximum angle θ for static equilibrium, which must be less than or equal to 45 degrees. The participants also explore the conditions under which the block remains at rest based on the coefficient of friction, leading to a need for corrections in algebraic expressions and logical sequences. The conversation emphasizes the importance of accurately applying physics principles and equations to solve the problem effectively.
Lito
Messages
9
Reaction score
0

Homework Statement



A block of mass M is positioned underneath an overhang that makes an angle θ > 0 with the vertical. You apply a horizontal force of Mg on the block, as shown in the figure. Assume that the friction force between the block and the overhang is large enough to keep the block at rest.

2uizynq.jpg


a. Make a free-body diagram of the block, indicating all external forces acting on it.

b. What are the normal force N and the friction forces F that the overhang exerts on the block?

c. Show that the overhang θ can be at most 45◦ if there is any chance that the setup is static.

d. Suppose the coefficient of friction is µ. For what range of angles θ does the block in fact remain at rest?

Homework Equations


(F⃗ net)x = ΣFx = 0

(F⃗ net)y = ΣFy = 0

fs≤μsN

The Attempt at a Solution


[/B]
a.
24fcs1t.jpg


b.
$$ \Sigma F_x=0 => N= Mgcos\theta-Mgsin\theta$$
$$ \Sigma F_y=0 => F_f= Mgcos\theta+Mgsin\theta$$
and also $$ F_f= \mu*N= \mu*Mg(cos\theta-sin\theta) $$

c.
I'm not sure what am I supposed to do…
Is it enough to state that in order that the friction will be positive the term (cos θ -sin θ) has to be positive.
Therefore for 0 < θ < 45 => 0 < (cos θ -sin θ) < 1 ?

d.
$$ F_{f(max)}= \mu*N \geq Mg(cos\theta+sin\theta) $$
$$\mu*Mg(cos\theta-sin\theta) \geq Mg(cos\theta+sin\theta) $$
$$\mu*cos\theta-cos\theta) \geq sin\theta+\mu*sin\theta $$
$$\mu-1 \geq tan\theta-\mu* tan\theta $$
$$\frac{\mu-1}{1-\mu} \geq tan\theta $$
$$-1 \geq tan\theta $$
then i get
$$90 \geq \theta \geq 135 $$
but it make no sense according to the previous section...

Thanks a lot :)
 
Physics news on Phys.org
In part b), reconsider your "and also". What are you assuming there that is beyond the information given?
Your answer to c) is on the right lines, but the logic sequence doesn't quite work. Start with "if theta > 45o then..."
Your algebra for d) has a sign error in the fourth line. Correct that and get a new expression for bounds on tan theta as a function of mu.
 
  • Like
Likes Lito
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top