Clausius Clapeyron Equation of lead

AI Thread Summary
The discussion focuses on using the Clausius-Clapeyron equation to estimate the melting point of lead at 100 atm, starting from its melting point at atmospheric pressure. The calculated melting point is approximately 600.754 K. A key point of contention is whether the assumption that L/T(delta V) remains constant is valid for this calculation. It is noted that while this assumption is commonly made, verification is necessary to ensure the accuracy of the result. The conversation emphasizes the importance of understanding the underlying principles of the Clausius-Clapeyron equation in thermodynamic calculations.
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Homework Statement



When lead is melted at atmospheric pressure the melting point is 327.0 degrees C, the density decreases from 1.101 x 10^4 to 1.065 x 10^4 kg/m^3 and the latent heat is 24.5 kJ/kg. Estimate the melting point of lead at a pressure of 100 atm.


Homework Equations





The Attempt at a Solution



Ok So i know how to get the right answer - which i think is 600.754 K as follows:

Clausius-C equation: dp/dT = L/T delta (V)

so i just say that delta p = L/T delta V delta T

Substituting in the values, I get the right answer..

My question is - why is this a valid move? surely it assumes L/T(deltaV) to be constant? Must it be?
 
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Yes, it's assumed that this factor is constant. This is something you'd have to verify to make sure the calculation is accurate.
 

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