# Clifford algebras with inverse?

1. Sep 21, 2010

### mnb96

Hello,
Let's assume we have a Clifford algebra of one of the following two kinds: $$\mathcal{C}\ell_{n,0}$$ or $$\mathcal{C}\ell_{0,n}$$.

Is it possible to say which algebras will admit a multiplicative inverse for each multivector element?

2. Sep 21, 2010

### arkajad

$$Cl_{0,1}=\bf{C}$$
$$Cl_{0,2}=\bf{H}$$

See the table on p. 11 in Atiyah, Bott, Shapiro "http://www.dleex.com/read/7878" [Broken]"

Last edited by a moderator: May 4, 2017
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