Closed-Form Solution for f(n) w/o Generating Fns

Tony11235
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f(n) = 0, n \leq 2

f(n) = \sqrt{n}f(\sqrt{n}) + n, n > 2

How can I get this in closed form? Generating functions won't work. Recuring a number of times hasn't worked out for me. Or can I show that f = O(n*lg(lg(n))), where lg stands for ln(n)/ln(2), without f being in closed form? Sorry for the poor tex skills.
 
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I don't think it can be put in closed form.

Daniel.
 
f(n)= kn for 2^{k}< n \le 2^{k+1}
 
HallsofIvy said:
f(n)= kn for 2^{k}< n \le 2^{k+1}

Are you serious? This is the closed form I've been struggling all day to find? Could you mention how you arrived at this? Sorry it's not totally obvious to me, I'm really tired.
 
Nevermind. No explanation needed. I'm just really pissed with myself.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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