Clovis's question at Yahoo Answers (bounded sequence)

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The discussion centers on the construction of a bounded sequence that lacks both maximum and minimum elements, specifically the sequence defined by \( a_n = \frac{(-1)^n n}{n+1} \). This sequence is bounded within the interval \([-1, 1]\) and demonstrates that it does not converge due to the existence of two subsequences approaching different limits, the infimum \( m \) and supremum \( M \). Since \( m \neq M \), the sequence cannot converge.

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Here is the question:

Construct a bounded sequence that has no maximum and no minimum element. Could a sequence like this converge? Why or why not?

Here is a link to the question:

Real Analysis Sequences 10pts? - Yahoo! Answers

I have posted a link there to this topic so the OP can find my response.
 
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Hello Clovis,

Consider the sequence $a_n=\dfrac{(-1)^nn}{n+1}$. Easily proved, $-1\leq a_n\leq 1$ for all $n$ and the sequence has no maximum and no minimum element.

Now, suppose $x_n$ is bounded sequence, then it has a infimum $m$ and a supremum $M$. If $x_n$ has no maximum and minimum, it has infinitely many elements close both infimum and supremum, so we can construct two subsequences $x_{n_k}\to m$ and $x_{n_r}\to M$. But $m\neq M$ (otherwise, $x_n$ would be a constant sequence, i.e. with maximum and minimum). This means that $x_n$ does not converge.
 

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