# Cluster Decomposition.Vanishing of the connected part of the S matrix.

• A
Im following Weinberg's QFT volume I and Im tying to show that the following equation vanishes at large spatial distance of the possible particle clusters (pg 181 eq 4.3.8):

$$S_{x_1'x_2'... , x_1 x_2}^C = \int d^3p_1' d^3p_2'...d^3p_1d^3p_2...S_{p_1'p_2'... , p_1 p_2}^C \times e^{i p_1' . x_1'}...$$

(i.e the fourier of the connected part of the corresponding S matrix element) vanishes when the distance between any two particles (states) is great.
He says that this only happens when this matrix element contains precisely one single delta function that ensures 3-momentum conservation:

$$S_{p_1'p_2'... , p_1 p_2}^C = \delta^3(p_1'+p_2'+... - p_1 - p_2)\times \delta(energy \ conservation) \times C_{p_1'p_2'... , p_1 p_2}$$

Can somebody tell my how this makes the first equation vanish when the relative distance of some states is large?

PD: sorry for the poor explanation but Im not gonna explain it better than Weinberg, Im just pointing out where Im having troubles.

Related High Energy, Nuclear, Particle Physics News on Phys.org
Suppose that one x under the integral (4.3.8) goes to infinity. This means that the integral over the corresponding p is a high-frequency Fourier transform of a smooth function. In the infinite frequency limit, such a Fourier transform goes to zero. The same is true when all x's go to infinity in different directions, i.e., all particles separate.

Eugene.

Alex Cros
Suppose that one x under the integral (4.3.8) goes to infinity. This means that the integral over the corresponding p is a high-frequency Fourier transform of a smooth function. In the infinite frequency limit, such a Fourier transform goes to zero. The same is true when all x's go to infinity in different directions, i.e., all particles separate.

Eugene.
I disagree, because translational invariance tells us that if all coordinates go to infinity together the S matrix should be invariant.
I think I solved the problem yesterday, when you integrate expression (with this 3-spacial delta) 4.3.8 the exponentials become "coupled" i.e. if you integrate say p_1 then the exponential for exp(i p_1 x_1) becomes exp(ix_1(-all other momenta)) then by the Riemann-Lebesgue theorem the integral vanishes when some of the coordinates go to infinity BUT NOT IF ALL go to infinity together since they would cancel and the theorem wouldn't apply.

Correct me if I am wrong!