CO2 and Kr Mixture: Calculating Original CO2 and Recoverable Kr Amounts

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The discussion centers on a problem involving a mixture of CO2 and Kr, where the total weight is 35.0 g and the initial pressure is 0.708 atm. After CO2 is removed, the pressure drops to 0.250 atm, prompting the need to calculate the original grams of CO2 and the recoverable grams of Kr. Participants are encouraged to use the partial pressure ratio as a molar ratio to derive the mass ratio, which will help in determining the individual masses of the gases. The conversation emphasizes that the problem should not be overly complex and encourages logical reasoning to arrive at the solution. Understanding the relationship between pressure and moles is key to solving the problem effectively.
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A misture of CO2 and Kr weighs 35.0 g and exerts a pressure of .708 atm in its container. Since Kr is expensive, you wish to recover it from the mixture. Afterthe CO2 is completely removed by absorption with NaOH(s), the pressure in the container is .250 atm. How many grams of CO2 were originally present? How many grams of Kr can you recover?

I have no idea how to do this?
Thanks
 
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It would be of no help if we will give you logical reason at first site, which you yourself think first pls reply with whatever you have thought while attempting the problem
 
Remember that the partial pressure ratio is the molar ratio. From the molar ratio calculate the mass ratio. From the mass ratio find the individual masses of the original compounds.

It shouldn't be too difficult.

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