Coefficient of Friction [Needing Help]

AI Thread Summary
The kinetic coefficient of friction between ice skates and ice is given as 0.01, and for a skater weighing 500 N, the average forward force required to maintain a constant velocity is calculated using the formula f = (Uk)(N). The calculation results in a force of 5 N, which the original poster questions due to its simplicity. Other participants confirm the calculation is correct, noting that the applied force equals the frictional force. The discussion clarifies the relationship between applied force and friction in this context.
pharmguy
Messages
8
Reaction score
0

Homework Statement


If the kinetic coefficient of friction between ice skates and ice is 0.01, what is the average forward force necessary for a 500 Nt skater to maintain a constant forward velocity?


Homework Equations


f = (Uk)(N)


The Attempt at a Solution



f = (Uk) (N)
f = (0.01) (500 Nt)
f = 5 Nt

Is this right? Just seems too simple. Can someone explain and walk me through this problem if I'm wrong.

Also I realized from a diagram I did in my head Fapp - f = 0
Fapp = f
Fapp = (Uk) (N)...right?
 
Physics news on Phys.org
Your calculation to get 5 N looks correct to me!
 
Alright thanks a bunch.
 

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
View full post »
Thread 'A cylinder connected to a hanging mass'

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
View full post »

Similar threads

How to find the coefficient of kinetic friction
Replies
4
Views
3K
Solve for friction coefficient of block on sp
Replies
1
Views
843
Calculate the coefficient of friction from mass and angle
Replies
5
Views
8K
Calculating acceleration from the coefficient of kinetic friction
Replies
48
Views
8K
Speed after gliding with friction force present using work/E
Replies
3
Views
4K
Finding the coefficient of Kinetic force with an angle
Replies
4
Views
1K
Ladder Leaning against wall -- find the coefficient of friction
Replies
5
Views
3K
Coefficient of kinetic friction?
Replies
21
Views
2K
How to find the coefficient of kinetic friction?
Replies
2
Views
2K
How to Derive the Coefficient of Friction from Time and Acceleration?
Replies
5
Views
2K

Hot Threads

Recent Insights

Back
Top