Coefficient of Friction [Needing Help]

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pharmguy
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Homework Statement


If the kinetic coefficient of friction between ice skates and ice is 0.01, what is the average forward force necessary for a 500 Nt skater to maintain a constant forward velocity?


Homework Equations


f = (Uk)(N)


The Attempt at a Solution



f = (Uk) (N)
f = (0.01) (500 Nt)
f = 5 Nt

Is this right? Just seems too simple. Can someone explain and walk me through this problem if I'm wrong.

Also I realized from a diagram I did in my head Fapp - f = 0
Fapp = f
Fapp = (Uk) (N)...right?
 
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Alright thanks a bunch.