Coefficient of Kinetic Friction Question

AI Thread Summary
To prevent slippage between two boxes accelerating at 2.5 m/s², the smallest coefficient of friction required is calculated using the formula a = μg, where g is the acceleration due to gravity (9.8 m/s²). The calculation yields a coefficient of kinetic friction (uk) of 0.25. However, it is noted that the coefficient of static friction (μs) is more relevant for preventing slippage. The method used for both coefficients is similar, confirming that the approach is correct. The distinction between static and kinetic friction is emphasized, but the calculation method remains applicable.
wilson_chem90
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1. If the acceleration of a pair of boxes has a magnitude of 2.5m/s^2, determine the smallest coefficient of friction between the boxes that will prevent slippage.



Homework Equations


F = ma
Fk = ukFn
Fw = mg


The Attempt at a Solution



ma = uk mg(Fn)
a = uk g
a/g = uk
2.5m/s^2 / 9.8m/s^2 = uk
uk = 0.25
 
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Since you don't want it to slip, it's really the coefficient of static friction you are interested in, but as to your solution, that looks like the right method.
 
oh okay, so its the same format just static friction?
 
wilson_chem90 said:
oh okay, so its the same format just static friction?

Correct.

μs not μk

No big deal.
 

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