Coefficient of static friction question

[Angelofhappiness]

Can anyone help?

The coefficient of static friction between hard rubber and normal street pavement is about 0.34. On how steep a hill (maximum angle) can you leave a car parked?

 

[Cyrus]

Show some work.

 

[Angelofhappiness]

Thats the thing, I have no idea where to begin. I know that us = 0.34 and acceleration = 0 which means Fnet = 0 but that's all.

 

[radou]

Thats the thing, I have no idea where to begin. I know that us = 0.34 and acceleration = 0 which means Fnet = 0 but that's all.

Yes, and it is all you need to know. Which forces are acting on the car on the incline?

 

[Cyrus]

Thats the thing, I have no idea where to begin. I know that us = 0.34 and acceleration = 0 which means Fnet = 0 but that's all.

If that is the case, you need to reread your book's chapter on this material and post your thoughts.

 

[Ja4Coltrane]

okay, recall that friction is the normal force times the static coefficient. You know that the car will slip when the force of the car down the hill equals the static friction. gravity causes both the normal force and the force down the incline, and these forces are perpendicular to each other, so just take some components of gravity.

 

[kcirick]

Draw a Free Body Diagram of the car. Then redraw the forces acting on it in components.