Coefficient of static friction question

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Homework Help Overview

The discussion revolves around determining the maximum angle at which a car can be parked on a hill, given the coefficient of static friction between hard rubber and pavement. The subject area pertains to static friction and forces acting on an incline.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants express uncertainty about how to start solving the problem, noting the coefficient of static friction and the condition of zero acceleration. Some inquire about the forces acting on the car on the incline and suggest considering the components of gravity.

Discussion Status

The discussion is ongoing, with participants seeking clarification on the forces involved and how to apply the concept of static friction. Some guidance has been offered regarding the importance of drawing a Free Body Diagram and considering the components of forces.

Contextual Notes

Participants have indicated a lack of understanding of the foundational concepts necessary to approach the problem, suggesting a need for review of relevant material.

Angelofhappiness
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Can anyone help?

The coefficient of static friction between hard rubber and normal street pavement is about 0.34. On how steep a hill (maximum angle) can you leave a car parked?
 
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Show some work.
 
Thats the thing, I have no idea where to begin. I know that us = 0.34 and acceleration = 0 which means Fnet = 0 but that's all.
 
Angelofhappiness said:
Thats the thing, I have no idea where to begin. I know that us = 0.34 and acceleration = 0 which means Fnet = 0 but that's all.

Yes, and it is all you need to know. Which forces are acting on the car on the incline?
 
Angelofhappiness said:
Thats the thing, I have no idea where to begin. I know that us = 0.34 and acceleration = 0 which means Fnet = 0 but that's all.

If that is the case, you need to reread your book's chapter on this material and post your thoughts.
 
okay, recall that friction is the normal force times the static coefficient. You know that the car will slip when the force of the car down the hill equals the static friction. gravity causes both the normal force and the force down the incline, and these forces are perpendicular to each other, so just take some components of gravity.
 
Draw a Free Body Diagram of the car. Then redraw the forces acting on it in components.
 

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