Solving Schrodinger Equation for Finite Potential Barrier

AI Thread Summary
The discussion focuses on solving the Schrödinger equation for a finite potential barrier, specifically where the potential is zero for x < 0 and a constant V0 for x > 0. The user has defined wave functions for both regions and established boundary conditions, including continuity of the wave function and its derivative at x = 0. They are looking to express the coefficients A, B, and C in terms of one another and relate them to reflection and transmission coefficients. Suggestions include consulting specific chapters from quantum mechanics textbooks for further guidance. The conversation emphasizes the importance of utilizing boundary conditions to derive the necessary relationships between the coefficients.
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Homework Statement


I am trying to find the coefficients in a Schrodinger equation approaching a finite potential.
https://www.physicsforums.com/showthread.php?t=203385
It is a problem similar to this, except a little easier. In my case, though, there is no V1 as shown in the picture at the thread, the potential is at x = 0 and doesn't drop back down, just continues going in the positive x direction. So at x = 0 it just goes straight up vertically, then levels off and keeps going, creating a sort of wall. (hope that is a good enough explanation)

Homework Equations


Schrodingers Equation


The Attempt at a Solution


I have defined the regions as:
Region 1: V(x) = 0 for x < 0
Region 2: V(x) = V0 for x > 0

I have used Schrodinger's Equation to get the wave function for each region:
Region 1:
Psi(x) = Aeik1x + Be-ik1x
With A being the incident wave and B being the reflected wave off of the potential barrier.
I also have K1 = (2mE/h2)1/2

Region 2:
Psi(x) = Ceik2x
With C being for the continuing wave, there is no reflected wave here because region 2 contains the barrier. I also think C would be considered T (transmitted).
I also have K2 = (2m(E-V0)/h2)1/2

So I can say that A + B = C at x = 0 (I think). I can also say that their derivatives are equal at that point, so ik1A - ik2B = ik2C

I also know that 1 = P(R) + P(T)
and R = abs(B2/A2)
and I have written T = 1 - R

I guess I'm supposed to solve B and C in terms of A, I'm almost positive all of the information thus far is correct, unless I just typed something incorrectly.

It's something that I haven't ever seen/done before so I'm absolutely stumped... I even looked at some old physics books from the library trying to get some ideas but am lost. I'm sure it's something really simple... I just need to know where to go from this point in order to solve for A B and C.

Thanks!
 
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so you have 2 equations linking A,B & C due to the boundary conditions (continuous wave function & derivative)

you should be able to solve for B & C in terms of A...
 


Well, it's not too bad. You can relate everything using your two equations at the boundary, and finding an expression for C/A and B/A. These expressions should end up containing k1 and k2.

You can then find a way to relate C/A and B/A to transmission and reflection coefficients.

I'm pretty sure most quantum texts discuss this - try ch. 7 of Liboff's book, or ch. 5 of Shankar's. This would be best classified as the single step potential.
 
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