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**[SOLVED] collision and impulse**

## Homework Statement

A 1.0 kg ball drops vertically onto a floor, hitting with a speed of 20 m/s. It rebounds with an initial speed of 5 m/s.

(a) What impulse acts on the ball during the contact?

kg·m/s

(b) If the ball is in contact with the floor for 0.020 s, what is the average force exerted on the floor?

N

## Homework Equations

p=m*v

deltap=J

F=m(deltav)/deltat

## The Attempt at a Solution

For (a) i used p=m*v and deltap=J

so I got (1*-20)-(1*5)=-25

and for (b) i used that F=(m*deltav)/deltat

which came out to be... 1(-25)/.020=0.5 N

both answers were wrong and I'm not sure what is wrong with the formulas I used...

Any help is appreciated! Thanks!