Collision and Momentum of Blocks

AI Thread Summary
The discussion centers on a collision scenario where block A slides into stationary block B, which has a mass of 5m. Participants debate whether the collision is elastic or inelastic, noting that while momentum is conserved, kinetic energy must also be conserved for the collision to be classified as elastic. The calculated velocity of block B after the collision is Vf = Vi/5, but there is uncertainty about the initial conditions and whether the problem statement is complete. It is emphasized that confirming the conservation of kinetic energy is crucial to determine the type of collision. The conversation highlights the importance of clarity in problem statements for accurate analysis.
Tim Wellens
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Homework Statement


If block A slides with a velocity into block B which is at rest, and after this collision block B ends up with a velocity and block A is stationary after. Block B has a mass of 5m.

Would this type of collision be an elastic collision or inelastic? How do you know?

What would the velocity of block B be after the collision?

Homework Equations


M1V1i+M2V2i=M1V1f+M2V2f

The Attempt at a Solution


I[/B]'m pretty sure this is an elastic collision problem because it seems as though the momentum is conserved and transferred from block A to block B.

This is what i did to figure the velocity of block b after the collision-
MVi+5MVi=MVf+5MVf
MVi+0=0+5MVf
MVi=5MVf
Vf=Vi/5

But I'm not sure if this is right or what I could do differently..
 
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Tim Wellens said:
I'm pretty sure this is an elastic collision problem because it seems as though the momentum is conserved
Momentum will certainly be conserved, but that does not make it elastic. In an elastic collision KE is conserved.
Can you work out whether KE is conserved?
Tim Wellens said:
Vf=Vi/5
Yes, although the question statements reads as though you left something out. Should it say "If block A slides with a velocity v into block B...", or somesuch? If so, you should use the same name for the given velocity in the answer.
 
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