Collision in 2 dimensions (Momentum)

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Homework Help Overview

The problem involves two spacecraft that are linked in space and then separated by springs, with the goal of determining their original speed when linked. The context is centered around momentum and collision in two dimensions.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to solve for the original speed of the spacecraft and questions whether calculations for the Y-axis are necessary given the initial conditions. Some participants confirm that focusing on the X-axis is appropriate, while others note the internal nature of the spring force.

Discussion Status

The discussion is ongoing, with participants providing feedback on the original poster's calculations and addressing assumptions about the forces involved. There is acknowledgment of the need to convert units for accurate calculations.

Contextual Notes

Participants are considering the implications of internal forces and the relevance of the Y-axis in their calculations, while also addressing unit conversion as a critical step in the problem-solving process.

MattsVai
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Homework Statement


Two spacecraft s have linked in space and are coasting with their engines off, heading directly towards Mars. The spacecraft s are thrust apart by large springs. Spacecraft 1 with mass of 1.9 x 10^4 kg, then has a velocity of 3.5 x 10^3 km/h at 5.1 degrees to its original direction. Spacecraft 2 with mass 1.7 x 10^4 kg, has then a velocity of 3.4 x 10^3 km/h at 5.9 degrees to its original direction. Determine the original speed of the two craft when they were linked together.
2. The attempt at a solution
Please see attached my attempt to solve this question. Am I on the right path? Do I have to calculate for Y axis too? Many thanks
 

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Last edited:
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Update:

So Basically, I know now that the force of the spring is in fact internal. But, if there is no velocity on the y-axis why would I have to calculate it? And I on the right path performing calculations for the x-axis only?

Cheers
 
You are indeed. The work done by the spring only acts in a Y direction so because of that, there is no change in speed in the x direction.
 
awesomeness... thank you
 
From looking at your work, you forgot to convert the speeds from Km/h into m/s before plugging the numbers into the equation.
 

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