A steel ball of mass 0.50 kg, moving with a velocity of 2.0 m/s [E], strikes a second ball of mass 0.30 kg, initially at rest. The collision is a glancing one, causing the moving ball to have a velocity of 1.5m/s [30 degrees N of E] after the collision. Determine the velocity of the second ball after the collision.
m1v1 + m2v2 = m1v1' + m2v2'
The Attempt at a Solution
I've tried using the y-component to solve for the speed on v2y' but there's no direction given so there are two variables to solve for. The final speed of the second ball and the direction of the second ball after the collision. Using the y-component i had the equation:
0 = (0.50)(1.5sin33) + (0.30)(v2')(siny)
How can I solve for both the speed and the direction? I've tried subbing in v2 in terms of siny but I just can't seem to get the right answer. Can someone solve this problem and show me how you solved it? Thanks.