Collision with an unknown mass and velocity after

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SUMMARY

The problem involves a collision between a 2 kg block sliding at 3 m/s and a static block of mass M on a frictionless surface. The final velocity of the 2 kg block after the collision is -1 m/s, indicating a reversal in direction. The calculations confirm that the mass M is 4 kg and the final velocity of mass M is 2 m/s, adhering to the principles of conservation of momentum and kinetic energy.

PREREQUISITES
  • Understanding of conservation of momentum
  • Familiarity with kinetic energy equations
  • Basic algebra for solving equations
  • Knowledge of collision types (elastic vs inelastic)
NEXT STEPS
  • Review conservation of momentum in collisions
  • Study elastic and inelastic collision differences
  • Practice solving collision problems with varying masses
  • Explore real-world applications of collision physics
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Students studying physics, particularly those focusing on mechanics and collision theory, as well as educators looking for examples of momentum conservation in action.

fantisism
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Homework Statement


You slide a 2 kg block on a flat icy surface towards a static block of mass M. Before the collision, the 2 kg mass is moving at 3 m/s. The total kinetic energy is not changed by the collision. After the collision, the 2 kg mass is moving at −1 m/s i.e. opposite to its original direction. Calculate the mass M in kg and the velocity of the mass M after the collision.

Homework Equations


Eq 1.) 0.5mv1i2+0.5Mv2i2=0.5mv1f2+0.5Mv2f2
Eq 2.) mv1i+Mv2i=mv1f+Mv2f

The Attempt at a Solution


I got v2f=2 m/s and M=4 kg. I solved for M for the second equation and substituted that in into the first equation.
 
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fantisism said:

Homework Statement


You slide a 2 kg block on a flat icy surface towards a static block of mass M. Before the collision, the 2 kg mass is moving at 3 m/s. The total kinetic energy is not changed by the collision. After the collision, the 2 kg mass is moving at −1 m/s i.e. opposite to its original direction. Calculate the mass M in kg and the velocity of the mass M after the collision.

Homework Equations


Eq 1.) 0.5mv1i2+0.5Mv2i2=0.5mv1f2+0.5Mv2f2
Eq 2.) mv1i+Mv2i=mv1f+Mv2f

The Attempt at a Solution


I got v2f=2 m/s and M=4 kg. I solved for M for the second equation and substituted that in into the first equation.
What is your question then? That result is correct.
 
ehild said:
What is your question then? That result is correct.
Oh sorry. I just wanted to make sure those were right because I tend to make small simple math errors. Thank you!
 
You are welcome:oldsmile:
 

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