How many different hands can be dealt in this variant of Poker?

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In a variant of Poker where each player is dealt 6 cards, the discussion focuses on calculating the number of possible hands for three pairs. The initial calculation of 1001 hands using combinations (13C3 + 12C3 + 11C3 + ... + 3C3) is noted, but it does not account for the variations in suits. Participants suggest a more systematic approach, emphasizing the need to first select three different card values and then determine the pairs for each value. The conversation highlights the importance of considering both card values and suits in the calculations. Accurate counting of hands requires careful consideration of these factors.
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In a varient of Poker each player is dealt a hand of 6 cards from a standard pack How many hands are there of each of the following types?

Three pairs: Two cards of the same value. another 2 of a differnt value, and a 3rd paid of a third value. i.e Q(clubs) Q(diamonds) 6(hearts) 6(diamonds) 4(spades) 4(hearts)

..

For my attempt I started with 13C3 + 12C3 +11C3 ... + 3C3 = 1001 different hands

But this hasn't accounted for the differnt variation of suits, threre are 6 possible pairs of suits, so i multiply 1001 by 6?

thanks for any help!
 
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Hi Firepanda! :smile:

Firepanda said:
For my attempt I started with 13C3 + 12C3 +11C3 ... + 3C3 = 1001 different hands

erm … 13C3 is the number of ways of choosing 3 cards out of 13 … but what did you think was the reason for adding 12C3 etc?

Be systematic. One step at a time.

First step: there have to be three different numbers (eg 2 5 Q).

Second step: for each number, there have to be 2 cards of that number.

Try it that way! :smile:
 
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