Combinatorics? Lottery, Canadians help?

flyingpig
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Homework Statement



My professor gave us this problem, I asked him about it but he just dumped it on me by saying "check it out yourself".

Problem

Determine the number of all combinations of winning numbers for Lotto 6/49

The Attempt at a Solution



I read on wikia there are actually 5 numbers? I am not sure if they repeat...if it even matters from a set of 49.

So my guess is

\binom{49}{6} = \frac{49!}{6!(49-6)!} = \frac{49 \cdot48 \cdot 47 \cdot 46 \cdot45 \cdot44}{6\cdot5 \cdot4\cdot3\cdot1} = 13983816

What's the problem? I don't know if 0 is in the set...
 
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flyingpig said:

Homework Statement



My professor gave us this problem, I asked him about it but he just dumped it on me by saying "check it out yourself".

Problem

Determine the number of all combinations of winning numbers for Lotto 6/49

The Attempt at a Solution



I read on wikia there are actually 5 numbers? I am not sure if they repeat...if it even matters from a set of 49.

So my guess is

\binom{49}{6} = \frac{49!}{6!(49-6)!} = \frac{49 \cdot48 \cdot 47 \cdot 46 \cdot45 \cdot44}{6\cdot5 \cdot4\cdot3\cdot1} = 13983816

What's the problem? I don't know if 0 is in the set...

Check out the page http://www.olg.ca/lotteries/draws_faq.jsp and look at the faq.

RGV
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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